The 1.8W on the standard Geode (lx800) is power consumption of the entire chipset, rather than the 1W for the CPU. The CPU itself runs at 0.9W. So, the Geode is still a lower power CPU. Once you add the more complex Unichrome 2 Pro graphics to the chipset, the VIA alternative will use quite a lot more.
It'll be interesting when Intel releases the Menlow@2W early next year, which has the performance of a Pentium M @800MHz with an updated GMA950 built in.
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AMD Already has 1w, 0.5w, and .25w Geode processors. How do these stack up?
...What?
The AMD Geode 500 MHz processor consumes 1.8W of power. This thing uses almost half the power for the same clockspeed.
http://en.wikipedia.org/wiki/AMD_Geode
The 1.8W on the standard Geode (lx800) is power consumption of the entire chipset, rather than the 1W for the CPU. The CPU itself runs at 0.9W. So, the Geode is still a lower power CPU. Once you add the more complex Unichrome 2 Pro graphics to the chipset, the VIA alternative will use quite a lot more.
It'll be interesting when Intel releases the Menlow@2W early next year, which has the performance of a Pentium M @800MHz with an updated GMA950 built in.
Ah, the Geodes are 1.5W@600MHz (LX900), 0.9W@500MHz (LX800) and 0.8W@433MHz (LX700). And those are just the processor cores - add on the support chips and you're looking at 3.2W, 2.4W and 1.9W respectively (plus memory). Where are you getting 0.5W and 0.25W from?
[AMD Geode™ LX Processor Family] http://www.amd.com/us-en/ConnectivitySolutions/ProductInformation/0,,50_2330_9863_13022%5E13057,00.html
Anthony, that's what I was thinking of. Thanks!